dre61126 dre61126
  • 12-01-2016
  • Mathematics
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SOLVING QUADRATIC EQUATIONS BY SQUARE ROOT
9p^2-6=642

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crisforp
crisforp crisforp
  • 12-01-2016
9p^2 - 6 = 642;  / + 6 ;
9p^2 = 648;       / ÷9 ;
p^2 = 72 ;
p = + [tex] \sqrt{72} or - \sqrt{72} [/tex];
Finally, p = +6[tex] \sqrt{2} [/tex] or p = -6[tex] \sqrt{2} .[/tex]
Answer Link
Billymkhoi
Billymkhoi Billymkhoi
  • 12-01-2016
9p^2-6=642
⇒ 9p^2= 642+6
⇒ 9p^2= 648
⇒ p^2= 648/9
⇒ p^2= 72
⇒ p= 6√(2) or p= -6√(2)

The final answer is p= 6√(2) or p= -6√(2)~
Answer Link

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